Worked example 1
In the PES of gaseous sulfur (Z = 16), what is the ratio of the 3p peak to the 3s peak?
Try it first: Write the configuration and read the two superscripts.
0 of 3 steps revealed.
What you'll be able to do: Read a PES spectrum: match peaks to subshells, use peak height for electron counts and binding energy for shell depth.
Best after: Electron Configurations and Orbital Filling, Shielding and Effective Nuclear Charge
Photoelectron spectroscopy is the direct experimental evidence for the shell and subshell model you have been using. Once you can read a spectrum, electron configuration stops being an assertion and becomes a measurement.
These are recommended, not required. You can start this lesson at any time.
High-energy photons knock electrons out of every occupied subshell at once. The instrument measures the energy needed to free each electron, called the binding energy, and plots how many electrons came off at each energy. The result is a bar-like spectrum with one peak per subshell.
Electrons closer to the nucleus are held more tightly, so core electrons appear at very high binding energy and valence electrons at low binding energy. For magnesium the peaks in order of decreasing binding energy are 1s, then 2s, then 2p, then 3s.
The height, or area, of a peak is proportional to the number of electrons in that subshell. For sulfur, [Ne] 3s² 3p⁴, the 3p peak is twice the height of the 3s peak, a 2:1 ratio, because 4 electrons versus 2. A filled p subshell against a filled s subshell gives 3:1.
S: 1s² 2s² 2p⁶ 3s² 3p⁴
The number of peaks equals the number of occupied subshells, not shells. Neon (1s² 2s² 2p⁶) has three peaks, with 1s at the highest binding energy. Magnesium (1s² 2s² 2p⁶ 3s²) has four peaks.
The 1s peak of oxygen sits at a much higher binding energy than the 1s peak of carbon, because oxygen has 8 protons pulling on its 1s electrons versus 6 for carbon, with essentially no shielding between them. Same subshell, more protons, deeper binding.
The energy required to eject a specific electron from an atom, measured directly in PES.
The number of peaks equals the number of occupied subshells.
Relative peak height or area gives the ratio of electrons in each subshell.
Binding energy increases closer to the nucleus and increases with nuclear charge for the same subshell.
In the PES of gaseous sulfur (Z = 16), what is the ratio of the 3p peak to the 3s peak?
Try it first: Write the configuration and read the two superscripts.
0 of 3 steps revealed.
How many peaks appear in the PES of neon, and which has the highest binding energy?
0 of 3 steps revealed.
Why it's wrong: 2s and 2p electrons have clearly different binding energies, so they give separate peaks.
Check instead: Count the terms in the full electron configuration.
Why it's wrong: Height reports how many electrons were ejected at that energy, not how tightly they were held.
Check instead: Use the horizontal position for binding energy and the height for electron count.
Why it's wrong: A filled 2p subshell with 6 electrons is taller than a 3s peak with 2, even though 3s is the valence subshell.
Check instead: Compare superscripts in the configuration to rank heights.
No practice questions are available for this topic yet. You can still practice the whole unit.
In a PES spectrum each peak is one subshell, peak height is proportional to the number of electrons in it, and binding energy increases for electrons closer to the nucleus and for higher nuclear charge.
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Data from the NIST Atomic Spectra Database