Worked example 1
Write the ground-state electron configuration of sulfur (S, Z = 16) in full and in noble-gas notation.
Try it first: Count 16 electrons across the table, stopping at sulfur.
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What you'll be able to do: Write the ground-state electron configuration of any main-group or first-row transition element.
Every periodic trend comes from where the electrons sit. This lesson builds the tool you will use for the rest of the unit: a reliable way to write out an electron configuration and read it off the periodic table itself.
These are recommended, not required. You can start this lesson at any time.
Electrons occupy shells (n = 1, 2, 3, ...) that contain subshells labelled s, p, d and f. An s subshell holds 2 electrons, p holds 6, d holds 10 and f holds 14. A configuration is just a tally: which subshells are occupied, and by how many electrons.
1s² 2s² 2p⁶ 3s² 3p⁶
Electrons fill from lowest energy upward: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p. You do not have to memorize this list. Walk across the periodic table row by row: groups 1-2 are the s block, groups 13-18 the p block, the middle ten columns the d block. The row number gives n for s and p, and n - 1 for d.
Replace the completed core with the previous noble gas in brackets. Sulfur is 1s² 2s² 2p⁶ 3s² 3p⁴, or [Ne] 3s² 3p⁴. Both are correct, but the short form makes the valence electrons obvious, and the valence electrons are what chemistry actually depends on.
S: [Ne] 3s² 3p⁴
For a main-group atom the valence electrons are those in the highest occupied n level, that is, everything written after the bracket. Oxygen ([He] 2s² 2p⁴) has 6 valence electrons in the n = 2 shell. Arsenic ([Ar] 4s² 3d¹⁰ 4p³) has 5 valence electrons, because the filled 3d electrons are core-like, not valence.
Chromium is [Ar] 4s¹ 3d⁵ and copper is [Ar] 4s¹ 3d¹⁰, not the naive 4s² 3d⁴ and 4s² 3d⁹. The 4s and 3d energies are extremely close in these atoms, and a half-filled or filled d subshell with reduced electron-electron repulsion comes out lower in energy. These two are the only exceptions you are expected to know at this level.
s holds 2, p holds 6, d holds 10, f holds 14 electrons.
Ground-state electrons occupy the lowest-energy orbitals available before higher ones.
The electrons outside the noble-gas core that participate in bonding, for main-group atoms the ns and np electrons.
In neutral atoms 4s is lower in energy than 3d, so it fills first. This ordering flips once the atom is ionized.
Write the ground-state electron configuration of sulfur (S, Z = 16) in full and in noble-gas notation.
Try it first: Count 16 electrons across the table, stopping at sulfur.
0 of 3 steps revealed.
Write the ground-state electron configuration of iron (Fe, Z = 26).
0 of 3 steps revealed.
Why it's wrong: In neutral atoms 4s is lower in energy and fills first, so the ground-state configuration lists 4s² before 3d.
Check instead: Follow the table order: the 4s block (period 4, groups 1-2) comes before the 3d block.
Why it's wrong: For arsenic, [Ar] 4s² 3d¹⁰ 4p³, the 3d¹⁰ electrons are buried and do not bond, so arsenic has 5 valence electrons, not 15.
Check instead: Count only the highest-n s and p electrons for main-group elements.
Why it's wrong: Only chromium and copper (and their heavier analogues) are expected exceptions. Manganese is a normal [Ar] 4s² 3d⁵.
Check instead: Assume the standard order unless the element is Cr or Cu.
No practice questions are available for this topic yet. You can still practice the whole unit.
Electron configurations follow the aufbau order, which the periodic table itself encodes block by block. Noble-gas notation shortens the core, and valence electrons are the ones outside that core.
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