Worked example 1
How many unpaired electrons are in a ground-state Mn²⁺ ion (Mn, Z = 25)?
Try it first: Decide which electrons manganese loses before you count anything.
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What you'll be able to do: Draw a correct orbital diagram and use it to count unpaired electrons and predict magnetic behaviour.
Best after: Electron Configurations and Orbital Filling
A configuration such as 2p⁴ tells you how many electrons are in a subshell, but not how they are arranged inside it. Two short rules settle the arrangement, and the arrangement is what determines whether a substance is attracted to a magnet.
These are recommended, not required. You can start this lesson at any time.
The Pauli exclusion principle says no two electrons in an atom can share all four quantum numbers. Practically: an orbital holds at most two electrons, and if it holds two they must have opposite spins, drawn as one up arrow and one down arrow in the same box.
Orbitals in the same subshell have equal energy. Electrons occupy them singly, all with the same spin, before any orbital gets a second electron. Nitrogen (2p³) therefore has three separate single electrons, not one pair plus one single.
N 2p: up | up | up
Write the configuration, fill the boxes of the last partly filled subshell using Hund''s rule, and count the boxes holding just one arrow. For Fe³⁺ ([Ar] 3d⁵) all five d orbitals hold one electron, giving 5 unpaired electrons, the maximum possible for a d subshell.
A species with at least one unpaired electron is paramagnetic and is drawn into a magnetic field. A species with every electron paired is diamagnetic and is weakly pushed out. Zn²⁺ ([Ar] 3d¹⁰) is diamagnetic, while Cu²⁺ ([Ar] 3d⁹) is paramagnetic with one unpaired electron.
A p subshell contains three equal-energy orbitals, and a d subshell contains five. For an oxygen atom, 2p⁴ must distribute as [↑↓] [↑] [↑] (the identity of the paired box is arbitrary). Two electrons remain unpaired, so an isolated ground-state O atom is paramagnetic. Merely seeing an even electron count does not imply all electrons are paired. In an orbital diagram, fill each box singly with parallel spins first, then add the opposite-spin partners; never put two same-spin arrows in one box. The magnetic behavior of a complex or solid can require extra information about bonding, so the simple count here applies to the stated atomic or free-ion configuration.
In a set of equal-energy p orbitals, place one electron in each box with parallel spins before pairing any. Then count the singly occupied boxes. An atom or ion with at least one unpaired electron is paramagnetic; if all electrons are paired, it is diamagnetic. A configuration tells you the subshell population, while the box diagram reveals the pairing.
Two electrons in the same orbital must have opposite spins, so an orbital holds a maximum of two.
Within a set of equal-energy orbitals, electrons occupy separate orbitals with parallel spins before pairing up.
Has one or more unpaired electrons and is attracted into a magnetic field.
Has all electrons paired and is very weakly repelled by a magnetic field.
How many unpaired electrons are in a ground-state Mn²⁺ ion (Mn, Z = 25)?
Try it first: Decide which electrons manganese loses before you count anything.
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Is Zn²⁺ paramagnetic or diamagnetic?
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For a ground-state oxygen atom (Z = 8), draw the 2p occupancy and predict its number of unpaired electrons.
Try it first: After [He] 2s², place four electrons in three p boxes.
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Draw the 2p part of carbon's orbital diagram and predict its magnetic behavior.
Try it first: Carbon is 1s² 2s² 2p²; distribute only the 2p electrons.
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Why it's wrong: Degenerate orbitals are equal in energy, and pairing costs repulsion energy, so electrons spread out first.
Check instead: Place one electron in every box of the subshell before adding a second to any box.
Why it's wrong: Magnetism depends on unpaired electrons, not on whether a subshell is occupied.
Check instead: Count arrows that are alone in a box. Zero alone means diamagnetic.
Why it's wrong: Once the atom has d electrons, the ns orbital is higher in energy, so ns electrons leave first.
Check instead: For Fe²⁺ start from [Ar] 4s² 3d⁶ and remove the 4s pair to get [Ar] 3d⁶.
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The Pauli exclusion principle limits an orbital to two electrons with opposite spins, and Hund's rule spreads electrons singly across degenerate orbitals first. Counting the leftover unpaired electrons tells you whether a species is paramagnetic or diamagnetic.
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