Worked example 1
For 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g), K = 4.0 × 10²⁴. Find K for 2 SO₃(g) ⇌ 2 SO₂(g) + O₂(g).
Try it first: Identify which of the three operations has been applied.
0 of 2 steps revealed.
What you'll be able to do: Find K for a target reaction by reversing, scaling and adding reactions whose constants are known.
Tables rarely list the exact reaction you need. Three simple rules let you build its K from reactions that are listed, in the same spirit as Hess's law.
These are recommended, not required. You can start this lesson at any time.
Swapping products and reactants swaps the numerator and denominator of the expression, so the new constant is the reciprocal of the old one. If K = 100 forward, the reverse reaction has K = 0.010.
K(reverse) = 1 / K(forward)
Doubling every coefficient doubles every exponent, which squares the whole expression. Halving the coefficients takes the square root. In general, multiplying by n raises K to the n.
K(new) = K(old)ⁿ
When two reactions are added, the intermediate cancels and the two expressions multiply together, leaving the expression for the overall reaction.
K(overall) = K₁ x K₂
The procedure is the same as for enthalpy: manipulate each given reaction until adding them reproduces the target, then combine the constants. The only difference is the arithmetic. Enthalpies are added and their signs flipped; constants are multiplied and inverted.
Do the reversal and the scaling on each individual reaction first, then multiply the adjusted constants together. Scaling a reaction that has already been reversed is fine as long as both operations are applied to the same constant.
K becomes 1/K.
K becomes Kⁿ.
Constants multiply.
Enthalpies add; equilibrium constants multiply.
A reaction that is barely product-favored forward must be reactant-favored in reverse.
K' = 1/K
K' = Kⁿ
K(total) = K₁ x K₂
For 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g), K = 4.0 × 10²⁴. Find K for 2 SO₃(g) ⇌ 2 SO₂(g) + O₂(g).
Try it first: Identify which of the three operations has been applied.
0 of 2 steps revealed.
For N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g), K = 6.0 × 10⁵. Find K for (1/2) N₂(g) + (3/2) H₂(g) ⇌ NH₃(g).
Try it first: Compare coefficients to find the scaling factor.
0 of 2 steps revealed.
Given A ⇌ B with K₁ = 2.0 and B ⇌ C with K₂ = 30, find K for A ⇌ C.
Try it first: Check that adding the two reactions cancels B.
0 of 2 steps revealed.
Why it's wrong: Equilibrium constants are never negative; the reverse constant is the reciprocal.
Check instead: Take 1/K.
Why it's wrong: Coefficients act as exponents, so halving means a square root.
Check instead: Raise K to the power n.
Why it's wrong: Enthalpies add, but the expressions for K multiply.
Check instead: Multiply the constants.
Why it's wrong: Both operations must act on the same reaction's constant.
Check instead: Adjust each reaction fully before combining.
No practice questions are available for this topic yet. You can still practice the whole unit.
Reversing a reaction inverts its constant, multiplying a reaction by a factor n raises the constant to the power n, and adding two reactions multiplies their constants. These rules follow directly from the algebra of the equilibrium expression. They mirror Hess's law, but where enthalpies are added, equilibrium constants are multiplied, and where an enthalpy sign flips, a constant is inverted. Applying the rules in the right order lets you assemble K for almost any target reaction from tabulated data.
This lesson is original Chem Help content. No external sources were adapted.