Worked example 1
For H₂(g) + I₂(g) ⇌ 2 HI(g), K = 50.0. Starting with 1.00 M H₂ and 1.00 M I₂, find the equilibrium concentrations.
Try it first: Write the change row using the coefficients 1, 1 and 2.
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What you'll be able to do: Set up an ICE table for any equilibrium and solve for the unknown concentrations, using the small-x approximation when it is valid.
Once you can predict direction, the natural next question is how far. An ICE table is the bookkeeping that turns a starting mixture and a value of K into actual equilibrium concentrations.
These are recommended, not required. You can start this lesson at any time.
Initial holds the concentrations before any reaction. Change holds the amounts consumed and formed, written in terms of x. Equilibrium is simply the sum of the two rows above. Everything you need for the K expression lives in the bottom row.
The changes follow the coefficients exactly. For N₂ + 3 H₂ ⇌ 2 NH₃ the changes are -x, -3x and +2x. Reactants that are consumed get a minus sign and products formed get a plus sign, and the multipliers are never optional.
If the mixture starts with products present, calculate Q first. When Q > K the reaction runs in reverse and the signs in the change row flip. Assigning the direction before writing the change row prevents a negative concentration later.
When an initial concentration is much larger than the expected change, replacing C − x with C may simplify the equilibrium equation. Whether this is valid depends on the reaction stoichiometry, K, and starting mixture; no single initial-concentration-to-K ratio works for every ICE table. Use the approximation to estimate x, then check the percent change in each concentration whose C ± change term you simplified.
After solving with an approximation, compare the magnitude of the concentration change with the nonzero initial concentration it was subtracted from or added to. If the change is 5% or less for each approximated concentration, the shortcut is acceptable; otherwise solve the full equation and keep only roots that give physically possible concentrations.
percent change = 100 × |concentration change| / initial concentration
An ICE table does not always start with products increasing. Calculate Q from initial concentrations when both sides are present: Q<K means forward change, Q>K means reverse change. Then use one variable x with stoichiometric coefficients and reject roots that imply negative concentrations.
A three-row layout of Initial, Change and Equilibrium concentrations used to solve equilibrium problems.
Every change is a coefficient multiple of x, negative for consumption and positive for formation.
The small-x approximation is acceptable when x is no more than 5% of the initial concentration.
A quadratic root that gives a negative concentration is discarded.
Compare Q with K before assigning signs in the change row.
x = (-b +/- sqrt(b² - 4ac)) / (2a)
(x / [A]0) × 100 <= 5%
For H₂(g) + I₂(g) ⇌ 2 HI(g), K = 50.0. Starting with 1.00 M H₂ and 1.00 M I₂, find the equilibrium concentrations.
Try it first: Write the change row using the coefficients 1, 1 and 2.
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For N₂O₄(g) ⇌ 2 NO₂(g), Kc = 4.6 × 10⁻³. Starting with 0.50 M N₂O₄, find [NO₂] at equilibrium.
Try it first: Set up the equilibrium expression, find a candidate x, and then check whether the concentration approximation is within 5%.
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For A(g) ⇌ B(g), K = 2.0, starting with 1.0 M A and 0.0 M B. Solve exactly.
Try it first: Would the small-x approximation be valid here?
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For A ⇌ B, K=4.0. Initially [A]=2.0 M and [B]=4.0 M. Find equilibrium concentrations.
Try it first: Qinitial = 4.0/2.0 = 2.0, below K.
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Why it's wrong: The change must be in the stoichiometric ratio.
Check instead: Copy each coefficient into the change row before substituting.
Why it's wrong: K is defined by equilibrium concentrations only.
Check instead: Always substitute the bottom row.
Why it's wrong: A large K means x is comparable to the initial concentration.
Check instead: Run the 5% check, or solve the quadratic from the start.
Why it's wrong: Concentrations cannot be negative.
Check instead: Discard that root and keep the physically possible one.
Why it's wrong: x is the extent of reaction, not necessarily the answer.
Check instead: Read the equilibrium row for the species asked about.
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An ICE table tracks Initial, Change and Equilibrium concentrations for every species. Changes follow the balanced equation’s stoichiometric ratios. Substituting the equilibrium row into K gives an equation in x. A small-x approximation may simplify that equation, but its validity depends on the reaction and starting mixture; estimate x and check the percent change in each concentration being approximated. If any change exceeds 5%, solve the full equation and keep only roots that give physically possible concentrations.
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