Worked example 1
Calculate the formal charge on nitrogen in NH₄⁺.
Try it first: Identify V, N and B for nitrogen before substituting.
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What you'll be able to do: Calculate the formal charge on any atom in a Lewis structure and check that the values sum correctly.
Best after: Drawing Lewis Structures Step by Step
Formal charge is a bookkeeping tool that tells you whether an atom is carrying its fair share of electrons.
These are recommended, not required. You can start this lesson at any time.
Formal charge = valence electrons - non-bonding electrons - half the bonding electrons. An equivalent phrasing is valence minus lone pair electrons minus the number of bonds, because each bond contributes one electron to the atom under this scheme.
Formal charge asks how many electrons an atom is assigned under equal sharing. Assign it every nonbonding electron on that atom and one electron from each shared pair. Subtract that assigned count from the neutral atom's valence contribution V. Thus FC = V − N_nonbonding − B_electrons/2. If using bond lines instead, count a single as one, a double as two and a triple as three; counting merely the number of neighboring atoms gives the wrong shortcut for multiple bonds.
For the oxygen in water: valence 6, non-bonding 4, bonding 4, so 6 - 4 - 2 = 0. For each hydrogen: 1 - 0 - 1 = 0. Neutral molecules drawn well usually give zero everywhere, which is a fast sanity check.
The notation N in the formula means the number of nonbonding electrons, not the number of lone pairs and not the element nitrogen. Three lone pairs mean six nonbonding electrons. For hydroxide O with three lone pairs and one bond, FC(O) = 6 − 6 − 1 = −1. For hydronium O with one lone pair and three bonds, FC(O) = 6 − 2 − 3 = +1. The reference valence contribution of oxygen stays six in both structures.
The formal charges of all atoms must add to the total charge on the species: zero for a neutral molecule, -1 for a 1- ion, +1 for a 1+ ion. If your values do not add up, either the arithmetic or the structure is wrong.
| Description | How bonding electrons are treated | Oxygen in H₂O |
|---|---|---|
| Formal charge | Split each pair equally | 0 |
| Oxidation number | Assign to the more electronegative atom | −2 |
| Partial charge | Model of the actual unequal electron distribution | Partially negative |
Formal charge and oxidation number are bookkeeping conventions; partial charge describes a partition of the actual electron density and is model dependent. A partial charge is not obtained by averaging those two integers, and it need not lie numerically between them in every species. The fact that BF₄⁻ formally assigns −1 to boron does not mean boron physically attracts the B–F bonding electrons more strongly than fluorine.
| Atom in nitrate contributor | V | Nonbonding electrons | Bond-order sum | Formal charge |
|---|---|---|---|---|
| Central N | 5 | 0 | 4 | +1 |
| Double-bonded O | 6 | 4 | 2 | 0 |
| Each single-bonded O | 6 | 6 | 1 | −1 |
The total is +1 + 0 − 1 − 1 = −1, matching nitrate. This sum works because every electron in the structure has been assigned once across all atoms. If the sum disagrees with the bracket charge, check the original budget, all lone pairs and each multiple-bond count. A correct sum is necessary but does not prove the drawing is the best contributor; several valid drawings can have the same net charge and different charge separation.
Valence electrons minus non-bonding electrons minus half of the bonding electrons.
Formal charge = valence contribution − nonbonding electrons − bond-order sum. A double bond counts two and a triple bond counts three in the last term.
Formal charges must add up to the overall charge on the molecule or ion.
5 - 0 - 4 = +1, which matches the 1+ charge on NH₄⁺.
FC = V - N - B/2
Calculate the formal charge on nitrogen in NH₄⁺.
Try it first: Identify V, N and B for nitrogen before substituting.
0 of 4 steps revealed.
Find the formal charges in the standard triple bonded structure of carbon monoxide, C triple bond O, with one lone pair on each atom.
Try it first: Treat each atom separately with the same formula.
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Find the formal charges in tetrafluoroborate, BF₄⁻.
Try it first: B has four single bonds; each F has one bond and three lone pairs.
0 of 3 steps revealed.
| Mistake | Why it's wrong | Check instead |
|---|---|---|
| Using the electron count drawn around the atom as the valence number V. | V is a property of the free atom taken from the periodic table. | Read V off the group before substituting. |
| Counting all bonding electrons instead of half. | Formal charge splits each bonding pair evenly between the two atoms. | Use the shortcut: subtract the number of bonds, not the number of bonding electrons. |
| Confusing formal charge with oxidation number. | Oxidation number assigns both bonding electrons to the more electronegative atom. | Ask which convention the question wants before calculating. |
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After the lesson · Question bank
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Formal charge equals the valence electrons of the free atom minus the non-bonding electrons minus half the bonding electrons. It assumes every bond is shared perfectly evenly, so it is bookkeeping rather than real charge, and the values must sum to the overall charge on the species.
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