Worked example 1
Electrolysis of molten NaCl. Write the electrode reactions and identify the sign of each electrode.
Try it first: Notice that with no water present, only Na⁺ and Cl⁻ can react.
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What you'll be able to do: Compare electrolytic and galvanic cells, assign electrode signs correctly, and predict the products of an electrolysis.
Best after: Standard Reduction Potentials and Cell Potential
A galvanic cell lets a favorable reaction pay you in electricity. An electrolytic cell does the reverse: you pay electricity to force an unfavorable reaction to run. Aluminum, chlorine, and every chrome bumper come from that bargain.
These are recommended, not required. You can start this lesson at any time.
If E°cell for a reaction is negative, the reverse process is spontaneous, but the forward one can still be forced by supplying electrical energy. That is electrolysis. Charging a rechargeable battery is the same idea: the cell operates galvanically while discharging and electrolytically while charging.
Electrolysis drives a reaction against its actual thermodynamic direction under the operating conditions. A negative E for the intended reaction means ΔrG = −nFE > 0 and external work is required. Negative E° is the standard-state version of that test; E° alone does not settle nonstandard conditions. Charging a rechargeable cell reverses its discharge chemistry through supplied electrical work, provided the chemistry and materials permit a reversible cycle.
applied voltage > |E°cell|
Oxidation is at the anode and reduction is at the cathode in both cell types. What changes is polarity. In a galvanic cell the anode is negative because it produces electrons; in an electrolytic cell the anode is positive because the power supply is pulling electrons out of it.
| Cell operation | Anode | Cathode | External electrical energy |
|---|---|---|---|
| Galvanic discharge | Oxidation, negative | Reduction, positive | Delivered by the reaction |
| Electrolytic drive | Oxidation, positive | Reduction, negative | Supplied to the reaction |
The power supply withdraws electrons from the electrolytic anode and delivers them to the cathode. Cations migrate toward the cathode and anions toward the anode in the ordinary electrolyte picture, while the actual electrode products depend on which species react. Polarity identifies the power connection; oxidation and reduction define the electrode names.
Thermodynamics gives the minimum voltage; reality demands more. Extra voltage, called overpotential, is needed to overcome the slow kinetics of forming gas bubbles at an electrode surface. Oxygen evolution has a particularly large overpotential, which is a major reason chlorine, not oxygen, is produced when concentrated brine is electrolyzed.
The reversible minimum opposing voltage follows the actual cell potential at the current activities. To pass useful current, additional applied voltage covers kinetic overpotentials at both electrodes and resistive iR losses. Gas evolution is often kinetically demanding, but overpotential is not simply the energy to make a visible bubble. Electrode material, current density, pH and concentration affect the competition, which is why thermodynamic tables alone may not select the observed brine anode product.
In an aqueous solution the solvent can be reduced (2 H₂O + 2 e⁻ → H₂ + 2 OH⁻) or oxidized (2 H₂O → O₂ + 4 H⁺ + 4 e⁻).
The species with the more positive reduction potential is reduced at the cathode, and the species easiest to oxidize reacts at the anode. Since Na⁺ reduction is at -2.71 V, far below water, aqueous sodium chloride yields hydrogen gas, not sodium metal.
2 H₂O + 2 e⁻ → H₂ + 2 OH⁻, E = -0.83 V at pH 7
To make sodium metal you must remove water entirely. In the Downs cell, molten NaCl is electrolyzed: sodium metal forms at the cathode and chlorine gas at the anode.
Aluminum is produced the same way from alumina dissolved in molten cryolite, a process that consumes a large fraction of the electricity used by heavy industry.
2 NaCl(l) → 2 Na(l) + Cl₂(g)
Electroplating deposits a thin metal layer by making the object the cathode in a solution of the plating metal. Anodizing thickens the oxide layer on aluminum by making it the anode. Both are electrolysis with a decorative or protective purpose.
In aqueous electrolysis, water can compete with dissolved ions. For CuSO₄ with inert electrodes under ordinary conditions, Cu²⁺ is reduced to copper at the cathode, while water is oxidized to O₂ at the anode rather than sulfate being oxidized. The solution becomes more acidic as H⁺ is generated. Electrode definitions still hold: reduction at cathode, oxidation at anode.
With inert electrodes in aqueous CuSO₄, a common ordinary-condition prediction is Cu²⁺ + 2 e⁻ → Cu at the cathode and 2 H₂O → O₂ + 4 H⁺ + 4 e⁻ at the anode. Balance electrons to obtain 2 Cu²⁺ + 2 H₂O → 2 Cu + O₂ + 4 H⁺. With a copper anode instead, Cu → Cu²⁺ + 2 e⁻ can replenish the ions plated at the cathode, giving metal transfer rather than the same net acid production. Specify whether electrodes are inert or reactive. In molten NaCl there is no water competitor, so Na⁺ can instead produce sodium metal.
A cell in which an external source drives a nonspontaneous redox reaction.
Electrolytic: anode positive, cathode negative. Galvanic: the reverse.
Oxidation at the anode and reduction at the cathode in both cell types.
Compare possible electrode reactions under actual conditions, including water, active electrode materials, activities and kinetic overpotentials; reduction need not produce a plated metal.
Extra voltage beyond the thermodynamic minimum, needed to overcome slow electrode kinetics.
Vapplied ≈ |Ereversible,opposing| + ηanode + ηcathode + iR
2 H₂O + 2 e⁻ → H₂(g) + 2 OH⁻
2 H₂O → O₂(g) + 4 H⁺ + 4 e⁻
Electrolysis of molten NaCl. Write the electrode reactions and identify the sign of each electrode.
Try it first: Notice that with no water present, only Na⁺ and Cl⁻ can react.
0 of 3 steps revealed.
Why does electrolysis of aqueous NaCl produce hydrogen instead of sodium metal at the cathode?
Try it first: Compare the two possible cathode reactions on a potential scale.
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For water electrolysis at 25 °C under the specified standard-state conditions, E°cell = −1.23 V. Distinguish the reversible opposing voltage from the applied voltage required for a measurable current.
Try it first: Separate the thermodynamic minimum from the practical requirement.
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Predict the usual electrode products for aqueous CuSO₄ at ordinary concentrations using inert electrodes, before substantial Cu²⁺ depletion.
Try it first: Consider Cu²⁺ versus water at the cathode and sulfate versus water at the anode.
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| Mistake | Why it's wrong | Check instead |
|---|---|---|
| Switching the anode to reduction in an electrolytic cell. | The definitions never change; only the polarity does. | Anode = oxidation, always. |
| Calling the electrolytic cathode positive. | The power supply forces electrons onto the cathode, making it negative. | Follow the electrons from the supply. |
| Predicting sodium metal from aqueous NaCl. | Water is reduced far more easily than Na⁺. | Always include water among the candidate reactions in aqueous electrolysis. |
| Assuming the thermodynamic voltage is enough in practice. | Overpotential from slow gas-forming kinetics adds a real extra requirement. | Use the actual reversible opposing potential as the thermodynamic baseline, then include kinetic and resistive losses for a working cell. |
| Thinking electrolysis violates thermodynamics. | Energy is supplied from outside, so the overall process still obeys the second law. | Account for the external work in ΔG. |
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After the lesson · Question bank
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An electrolytic cell uses an external source to drive a reaction against its actual thermodynamic direction. The anode remains the oxidation site and is positive; the cathode remains the reduction site and is negative. Applied voltage must overcome the actual reversible opposing potential plus kinetic and resistive losses. Predict products by considering water, ion activities, electrode material and competing reactions. Molten salts remove water from that competition.
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Source rights and review statusLesson-specific rights and provenance need review.
The current online Chemistry 2e edition lists CC BY-NC-SA 4.0. The source version used for this lesson and its applicable rights remain unverified.
Recorded use: further reading. The source record also indicates adaptation or summary; exact passages and applicable terms still need verification.
Recorded attribution / license claim (applicability unverified): Access for free at openstax.org
Source rights and review status