Worked example 1
Predict the molecular shape and approximate bond angle of NH₃, and state whether it is polar.
Try it first: Count domains on nitrogen before naming anything.
0 of 5 steps revealed.
What you'll be able to do: Convert a domain count and lone pair count into a molecular shape with predicted bond angles.
Best after: Counting Electron Domains
Once you can count domains, the shape follows from a short table, and lone pairs explain every deviation from the ideal angle.
These are recommended, not required. You can start this lesson at any time.
With four domains: no lone pairs gives tetrahedral, one lone pair gives trigonal pyramidal, two lone pairs gives bent. With three domains: no lone pairs gives trigonal planar, one lone pair gives bent. With five domains: zero through three lone pairs give trigonal bipyramidal, seesaw, T-shaped and linear. With six domains: zero through two lone pairs give octahedral, square pyramidal and square planar.
A lone pair is held by only one nucleus, so its electron cloud spreads wider than a bonding pair and pushes harder. Methane has ideal 109.5 degree angles, ammonia drops to about 107 degrees with one lone pair, and water drops to about 104.5 degrees with two. The same reasoning explains why PH₃ has angles near 93 degrees, closer to pure p orbital character than NH₃.
A molecule is polar when polar bonds fail to cancel. CO₂ is linear, so its two bond dipoles cancel and the molecule is nonpolar. Water is bent, so its dipoles add and the molecule is strongly polar. Symmetric shapes such as tetrahedral CCl₄ and square planar XeF₄ cancel; asymmetric shapes such as trigonal pyramidal NH₃ and seesaw SF₄ do not.
Lone pairs go equatorial because that position has only two neighbours at 90 degrees instead of three.
Linear 180, trigonal planar 120, tetrahedral 109.5, trigonal bipyramidal 120 and 90, octahedral 90.
Two bonded atoms with one or two lone pairs on the central atom.
Five domains with one lone pair gives a seesaw shape and a net dipole.
shape = f(bonding domains, lone pairs)
Predict the molecular shape and approximate bond angle of NH₃, and state whether it is polar.
Try it first: Count domains on nitrogen before naming anything.
0 of 5 steps revealed.
Why is XeF₄ nonpolar even though every Xe-F bond is polar?
Try it first: Work out the domain count for xenon.
0 of 4 steps revealed.
Why it's wrong: Molecular shape names the atoms only, and water has just two bonded atoms.
Check instead: Name the shape from bonded atoms, and use the domain count only to set the framework.
Why it's wrong: An axial lone pair would face three neighbours at 90 degrees instead of two.
Check instead: Always place lone pairs equatorially in five-domain systems.
Why it's wrong: Symmetric geometry can cancel the individual bond dipoles.
Check instead: Add the bond dipoles as vectors using the predicted shape.
No practice questions are available for this topic yet. You can still practice the whole unit.
Molecular geometry follows from the number of domains and how many of them are lone pairs. Lone pairs occupy more angular space than bonding pairs, so they compress the remaining bond angles below the ideal value, and in a trigonal bipyramid they always take equatorial positions.
This lesson is original Chem Help content. No external sources were adapted.