Region 1, before any base, is a weak acid ICE problem. Region 2 is a buffer, handled with Henderson-Hasselbalch on moles. Region 3, the half-equivalence point, has equal moles of acid and conjugate base, so pH = pKa and the curve is at its flattest. Region 4, equivalence, is a solution of the conjugate base alone, so it is basic. Region 5 is governed by excess strong base.
For 25.00 mL of 0.100 M acetic acid, Ka = 1.80 × 10⁻⁵, titrated with 0.100 M NaOH at 25 °C, initial acid is 2.500 mmol and Veq = 25.00 mL:
At equivalence the original HA has been stoichiometrically converted, but the product A⁻ hydrolyzes; it is not a buffer containing equal prepared amounts. Just before or after equivalence, use the method whose species assumptions remain valid rather than forcing every point into Henderson–Hasselbalch.