Organic ChemistryOrganic ReactionsContent level: Core 18 min

Organic Reactions: Substitution, Addition and Combustion

What you'll be able to do: Classify an organic reaction as substitution, addition, elimination, condensation or combustion and predict its organic product.

Introduction

Most introductory organic reactions fall into a short list of types. Once you can name the type from what happens to the bonds, predicting the product becomes routine.

These are recommended, not required. You can start this lesson at any time.

Learning objectives

  • Classify reactions as substitution, addition, elimination, condensation or combustion
  • Predict the product of halogenation, hydrogenation, hydration and hydrohalogenation
  • Write and balance complete and incomplete combustion equations
  • Recognise esterification and hydrolysis as condensation and its reverse

Lesson

Substitution

One atom or group is swapped for another while the carbon skeleton stays intact. Alkanes undergo free-radical halogenation with a halogen under UV light, and haloalkanes are substituted by nucleophiles such as OH to give alcohols.

CH + Cl → CHCl + HCl (UV light)

Addition

A pi bond opens and two fragments add across it, so a double bond becomes single. Hydrogenation adds H over a metal catalyst; halogenation adds Br; hydration adds water with an acid catalyst; hydrohalogenation adds HX. Only unsaturated molecules can undergo addition.

CH=CH + Br → CHBr–CHBr

Bromine water losing its orange colour is the classic test for a C=C or C≡C.

Elimination

The reverse of addition: a small molecule such as HO or HX leaves and a pi bond forms. Dehydrating an alcohol with concentrated sulfuric acid gives an alkene.

CHCHOH → CH=CH + HO (conc. HSO, heat)

Condensation and hydrolysis

Two molecules join and expel a small molecule, almost always water. A carboxylic acid plus an alcohol gives an ester; an acid plus an amine gives an amide, which is the peptide bond of proteins. Hydrolysis runs the process backwards by adding water.

CHCOOH + CHCHOH ⇌ CHCOOCHCH + HO

Combustion

Complete combustion in plenty of oxygen gives CO and HO and releases a lot of energy. Limited oxygen gives incomplete combustion, producing CO or soot along with water. Balance combustion by carbons first, then hydrogens, then oxygens last.

CH + 5 O3 CO + 4 HO

Incomplete combustion produces carbon monoxide, which is toxic and colourless.

Key ideas

Definition
Substitution

An atom or group replaces another; the number of bonds to carbon does not change.

Definition
Addition

Two fragments add across a multiple bond, reducing unsaturation.

Definition
Condensation

Two molecules join with the loss of a small molecule, usually water.

Rule
Saturated vs unsaturated

Alkanes substitute; alkenes and alkynes add.

Rule
Balancing combustion

Balance C, then H, then O, and use fractional O coefficients before doubling if needed.

Equation
Complete combustion of an alkane

CₙHₙ₊ + ((3n + 1)/2) O → n CO + (n + 1) HO

  • n = carbon atoms in the alkane
Equation
Hydrogenation

R–CH=CH–R′ + H → R–CH–CH–R′ (Ni or Pt)

  • H = hydrogen added across the double bond
Equation
Esterification

R–COOH + R′–OH ⇌ R–COO–R′ + HO

  • HO = the small molecule lost in condensation

Worked examples

Worked example 1

Write the balanced equation for the complete combustion of butane, CH₁₀.

Try it first: Balance the carbons and hydrogens before you touch the oxygens.

    0 of 4 steps revealed.

    Worked example 2

    Propene reacts with bromine. Name the reaction type and give the product.

    Try it first: What kind of bond does propene have that propane does not?

      0 of 4 steps revealed.

      Common mistakes

      Expecting an alkene to undergo substitution with Br.

      Why it's wrong: The pi bond is more reactive than any C–H bond, so bromine adds across it instead of replacing hydrogen.

      Check instead: Check for unsaturation first: unsaturated means addition, saturated means substitution.

      Balancing oxygen before carbon and hydrogen in a combustion equation.

      Why it's wrong: Oxygen appears in two products, so its count keeps changing until the others are fixed.

      Check instead: Balance C, then H, then O, allowing a fractional O and doubling at the end.

      Forgetting the water in esterification.

      Why it's wrong: Condensation always expels a small molecule, so the equation will not balance without it.

      Check instead: Count atoms on both sides and add HO to close the gap.

      Practice this skill

      No practice questions are available for this topic yet. You can still practice the whole unit.

      What you should now know

      Organic reactions sort into a few types. Substitution swaps one group for another and is typical of saturated alkanes and haloalkanes. Addition opens a pi bond so two fragments attach, covering hydrogenation, halogenation, hydration and hydrohalogenation of alkenes and alkynes. Elimination reverses addition by expelling a small molecule and creating a pi bond. Condensation joins two molecules and releases water, as in esterification and amide formation, and hydrolysis reverses it. Combustion gives CO and HO when oxygen is plentiful and CO or soot when it is not.

      • Saturated molecules substitute; unsaturated molecules add
      • Addition removes unsaturation, elimination creates it
      • Condensation expels water; hydrolysis puts it back
      • Balance combustion equations C, then H, then O
      • Decolourising bromine water is the standard test for a C=C or C≡C

      Sources and further reading

      This lesson is original Chem Help content. No external sources were adapted.