Worked example 1
For Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s), identify what is oxidised, what is reduced, and both agents.
Try it first: Assign oxidation numbers to zinc and copper on each side before looking at the sulfate.
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What you'll be able to do: Decide whether a reaction is redox, and name the species oxidised, reduced, and acting as each agent.
Once oxidation numbers can be assigned, spotting a redox reaction becomes mechanical: compare each element before and after. If nothing changed, no electrons moved, and the reaction is something else.
These are recommended, not required. You can start this lesson at any time.
Assign oxidation numbers to every atom on both sides. Oxidation is an increase in oxidation number, reduction is a decrease. If every element keeps its number, no electrons were transferred and the reaction is not redox, no matter how dramatic it looks.
The oxidising agent is the species that causes oxidation in something else, which means it is itself reduced. The reducing agent is the species that is itself oxidised. Students lose more marks here than anywhere else in the unit, so state which species changed first, then attach the agent label second.
Every electron lost by one species is gained by another. If one atom rises by 2 and another falls by 1, then two of the second atom must be involved. This is the arithmetic that makes balancing redox equations possible.
Zn → Zn²⁺ + 2 e⁻ paired with Cu²⁺ + 2 e⁻ → Cu
Single replacement and combustion are always redox. Synthesis and decomposition are redox when a free element is involved on either side. Double replacement, precipitation and acid-base neutralisation are never redox, because the ions keep the same charges throughout.
Occasionally a single element is both oxidised and reduced in the same reaction. Chlorine in cold sodium hydroxide goes from 0 to -1 and to +1 at the same time. Check every element individually rather than stopping at the first change you find.
Loss of electrons, shown by an increase in oxidation number.
Gain of electrons, shown by a decrease in oxidation number.
The species that accepts electrons and is therefore itself reduced.
The species that donates electrons and is therefore itself oxidised.
Oxidation and reduction occur together, and the electrons lost equal the electrons gained.
For Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s), identify what is oxidised, what is reduced, and both agents.
Try it first: Assign oxidation numbers to zinc and copper on each side before looking at the sulfate.
0 of 4 steps revealed.
Is AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq) a redox reaction?
Try it first: Look for any free element, then check each ion charge.
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In 2 MnO₄⁻ + 5 H₂C₂O₄ + 6 H⁺ → 2 Mn²⁺ + 10 CO₂ + 8 H₂O, identify the oxidising agent.
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Why it's wrong: An agent acts on something else, so the oxidising agent is the one being reduced.
Check instead: Identify the change first, then flip the label.
Why it's wrong: The modern definition is electron loss, and many redox reactions involve no oxygen at all.
Check instead: Compare oxidation numbers rather than looking for O atoms.
Why it's wrong: Precipitation and acid-base reactions also change appearance without transferring electrons.
Check instead: Assign oxidation numbers on both sides and compare.
Why it's wrong: Disproportionation involves one element changing in two directions.
Check instead: Check every element before concluding.
No practice questions are available for this topic yet. You can still practice the whole unit.
Oxidation is a rise in oxidation number caused by electron loss, and reduction is a fall caused by electron gain. The two always happen together and in matching electron amounts. The species that is oxidised is the reducing agent, and the species that is reduced is the oxidising agent, a pairing that is easy to reverse if you name it carelessly.
This lesson is original Chem Help content. No external sources were adapted.