Worked example 1
Write the ground-state electron configuration of a sulfur atom (Z = 16) and state how many unpaired electrons it has.
Try it first: Fill subshells in n + l order and stop at 16 electrons.
0 of 4 steps revealed.
What you'll be able to do: Apply the Aufbau, Pauli and Hund rules to build orbital diagrams and to work out ion configurations.
Best after: Orbitals, Subshells and Quantum Numbers
Three short rules decide the order electrons fill orbitals, and they explain magnetism and ion charges alike.
These are recommended, not required. You can start this lesson at any time.
Electrons occupy the lowest-energy subshell available. Order the subshells by n + l, and break ties by choosing the smaller n. That is why 4s (4 + 0 = 4) fills before 3d (3 + 2 = 5), and why 4p (5) fills after 3d even though both come before 5s (5, but with larger n).
The Pauli exclusion principle says no two electrons in an atom can share all four quantum numbers, which caps every orbital at two electrons with opposite spins. Hund rule says that within a set of degenerate orbitals, electrons spread out singly with parallel spins before any orbital takes a second electron, because pairing costs repulsion energy. Nitrogen therefore has three unpaired 2p electrons, not one pair and one single.
When a transition metal ionizes, electrons leave the highest n first, so the 4s electrons go before the 3d electrons. Vanadium [Ar] 4s² 3d³ becomes V³⁺ with configuration [Ar] 3d². A species with any unpaired electrons is paramagnetic and is attracted to a magnetic field; a species with all electrons paired is diamagnetic.
Fill the lowest-energy subshell first, ordered by n + l with ties broken by smaller n.
Two electrons in the same orbital must have opposite spins.
Half-fill degenerate orbitals with parallel spins before pairing.
Iron is [Ar] 4s² 3d⁶, so Fe²⁺ is [Ar] 3d⁶ with four unpaired electrons and is paramagnetic.
lower n + l fills first
unpaired = number of singly occupied orbitals
Write the ground-state electron configuration of a sulfur atom (Z = 16) and state how many unpaired electrons it has.
Try it first: Fill subshells in n + l order and stop at 16 electrons.
0 of 4 steps revealed.
What is the electron configuration of Fe³⁺ (Z = 26)?
Try it first: Write neutral iron first, then decide which electrons leave.
0 of 3 steps revealed.
Why it's wrong: Pairing raises energy through electron repulsion, so Hund rule forbids it in the ground state.
Check instead: Place one electron in each degenerate orbital before doubling up.
Why it's wrong: Once 3d is occupied it drops below 4s in energy, so 4s electrons are the outermost.
Check instead: Take electrons from the highest principal quantum number first.
Why it's wrong: A d¹⁰ ion such as Zn²⁺ has every electron paired.
Check instead: Draw the orbital diagram and count singly occupied orbitals.
No practice questions are available for this topic yet. You can still practice the whole unit.
Electrons fill the lowest available energy subshell first (Aufbau, ordered by the n + l rule), no two electrons share all four quantum numbers (Pauli), and degenerate orbitals each take one electron with parallel spin before pairing (Hund). Transition metals lose their outer s electrons before their d electrons when they ionize.
This lesson is original Chem Help content. No external sources were adapted.