Worked example 1
For A ⇌ B in an ideal dilute solution, Kc = 100. The total concentration [A] + [B] is 0.101 M. Find the equilibrium concentrations.
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What you'll be able to do: Describe what is happening at the particle level at equilibrium and interpret the size of K.
A reaction that reaches equilibrium has not stopped. Forward and reverse changes are still happening, just at matching rates, so the amounts you can measure stop changing.
These are recommended, not required. You can start this lesson at any time.
If the initial mixture contains reactants but no products, the forward reaction initially occurs without a reverse reaction. If both are present initially, both directions can occur from the start. As product builds up the reverse reaction speeds up and the forward reaction slows down. Eventually the two rates become equal. From that moment the measurable concentrations stop changing, but individual molecules are still converting in both directions.
For the elementary idealized pair A ⇌ B, equilibrium requires kf[A] = kr[B]. Thus [B]/[A] = kf/kr, while the two concentrations can be very different. This ratio-of-rate-constants result applies directly to this elementary pair; it is not a rule to take arbitrary overall reaction orders from its coefficients. A constant bulk composition also needs stable external conditions and no net addition, removal or competing process.
A common trap is to read equilibrium as meaning equal concentrations of reactants and products. It means equal rates. The actual amounts at equilibrium depend on the reaction and can be wildly lopsided.
For a general reaction aA + bB ⇌ cC + dD, the equilibrium constant compares product terms to reactant terms, each raised to its coefficient. The value is constant at a fixed temperature no matter what starting amounts you used.
K = ([C]ᶜ [D]ᵈ) / ([A]ᵃ [B]ᵇ)
For A ⇌ B, Kc = [B]/[A], so Kc = 100 means one hundred B particles per A particle in an ideal mixture. Here a large K directly means B dominates. For A ⇌ 2 B, however, Kc = [B]²/[A]; its size is not a simple mole fraction. Initial amounts, total concentration and stoichiometric powers are needed to calculate the composition. “Products favored” describes the equilibrium activity expression relative to the chosen standard states, not a universal guarantee that every product is more concentrated than every reactant.
Likewise K ≈ 1 means neither side of the activity ratio is strongly favored; it does not require equal concentrations or equal total moles. Always write the balanced reaction and its expression before interpreting a numerical K. Reversing or scaling the equation also changes the reported K.
For a specified reaction, its thermodynamic equilibrium constant depends on temperature. At fixed temperature, changing concentrations or gas volume can change Q and may cause a shift until Q again equals K. A catalyst alone changes neither K nor the equilibrium composition; it provides a faster pathway for both directions. If the mixture is already at equilibrium, it remains there.
At fixed temperature, two sealed preparations with different total inventories can have different equilibrium concentrations while satisfying the same expression. For A ⇌ B with K = 2, total concentration 0.300 M gives [A] = 0.100 and [B] = 0.200 M, while total 0.600 M gives 0.200 and 0.400 M. Position means the resulting composition; K is the constraint on its ratio. A catalyst changes the rates of interconversion, not the value of that ratio. A very large K does not reveal whether equilibrium will be reached in seconds or centuries.
At equilibrium the forward and reverse rates are equal, so bulk concentrations remain steady. A labeled atom introduced into one side can still appear in products as the reactions continue.
The label changes what is traceable, not the principle: a constant macroscopic composition can conceal molecular exchange in both directions.
A state where the forward and reverse reactions proceed at equal rates, so concentrations remain constant.
The fixed ratio of product to reactant terms, each raised to its stoichiometric coefficient, at a given temperature.
For a specified reaction and standard-state convention, thermodynamic K depends on temperature. Concentration or volume can change Q and equilibrium composition; a catalyst changes neither K nor the equilibrium composition.
A catalyst changes how fast equilibrium is reached, never where it lies.
A system reaches the same K whether it starts from pure reactants or pure products.
K = ([C]ᶜ [D]ᵈ) / ([A]ᵃ [B]ᵇ)
For A ⇌ B in an ideal dilute solution, Kc = 100. The total concentration [A] + [B] is 0.101 M. Find the equilibrium concentrations.
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A sealed flask of H₂ and I₂ reaches equilibrium with HI. A student says the reaction has stopped. Correct the statement.
Try it first: Ask what would happen to a labelled iodine atom after equilibrium is reached.
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What does adding a catalyst do (i) to a mixture approaching equilibrium and (ii) to a mixture already at equilibrium, at unchanged temperature?
Try it first: Recall which activation energies a catalyst lowers.
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At equilibrium A ⇌ B, a small amount of isotopically labeled A is introduced without materially disturbing the mixture. Will labeled B eventually appear?
Try it first: Ask whether the forward reaction stops at equilibrium.
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| Mistake | Why it's wrong | Check instead |
|---|---|---|
| Reading equilibrium as equal concentrations of reactants and products. | Equilibrium equalises rates, not amounts. | Use K to judge which side is favored. |
| Saying the reaction stops at equilibrium. | Molecules keep converting in both directions; only the net change is zero. | Describe it as no net change rather than no reaction. |
| Claiming a catalyst increases the yield at equilibrium. | It accelerates both directions equally. | Change temperature if you want to change K. |
| Thinking K depends on the starting concentrations. | Different starting amounts settle to different concentrations but the same ratio. | Remember K is fixed by temperature alone. |
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After the lesson · Question bank
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34 topic questions across 3 difficulty levels.
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At equilibrium the forward and reverse reactions occur at equal rates, so concentrations stay constant while molecules keep reacting. This is why equilibrium is called dynamic rather than static. The equilibrium constant K is a fixed number at a given temperature that compares products to reactants. A large K means products dominate at equilibrium, a small K means reactants do, and K near 1 means both are present in comparable amounts. For the specified reaction, K depends on temperature. Concentration or gas-volume changes may shift the composition at fixed temperature without changing K; a catalyst alone changes neither K nor the equilibrium composition.
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