Worked example 1
Identify the conjugate acid-base pairs in NH₃ + H₂O → NH₄⁺ + OH⁻.
Try it first: Track the hydrogen atoms, one of them changes owner.
0 of 3 steps revealed.
What you'll be able to do: Describe neutralisation as proton transfer, identify conjugate pairs and predict the products of an acid-base reaction.
Acid-base chemistry is easier once you stop thinking about litmus paper and start thinking about one particle: the proton. Every reaction in this lesson is a hydrogen ion moving from one species to another.
These are recommended, not required. You can start this lesson at any time.
The Bronsted-Lowry definition is deliberately simple: an acid donates H⁺, a base accepts it. Because a hydrogen ion is just a bare proton, the whole of acid-base chemistry becomes bookkeeping about where that proton goes.
Nothing else needs to change for a reaction to count as acid-base.
HA + B → A- + HB⁺
When an acid gives up its proton, what remains is its conjugate base. When a base accepts a proton, the result is its conjugate acid. Members of a pair always differ by exactly one H and one unit of charge. HCl and Cl⁻ are a pair; H₂O and OH⁻ are a pair; H₂O and H₃O⁺ are also a pair, which is why water appears on both sides of so many equations.
In CH₃COOH + NH₃ ⇌ CH₃COO⁻ + NH₄⁺, trace the hydrogen rather than pairing reactants by position. Acetic acid and acetate are one pair; ammonia and ammonium are the other. Removing H⁺ lowers a species' charge by one; adding H⁺ raises it by one. Thus removing H⁺ from neutral CH₃COOH gives −1 acetate, while adding H⁺ to neutral NH₃ gives +1 ammonium. The total charge stays zero. An oxygen atom or an electron is not transferred in this bookkeeping.
Strong acids such as HCl, HBr, HI, HNO₃, HClO₄ and commonly HClO₃ transfer their protons essentially completely to water under the conditions of introductory problems. Sulfuric acid requires a qualification: its first ionization is strong, but HSO₄⁻ loses its second proton through a separate, incomplete equilibrium. Complete neutralization by sufficient strong base can nevertheless consume two OH⁻ per H₂SO₄.
Group 1 hydroxides and dissolved Ca(OH)₂, Sr(OH)₂ and Ba(OH)₂ supply hydroxide essentially completely. Solubility and base strength are different: limited dissolution of a solid does not make its dissolved portion a weak base. A weak acid or base has an incomplete reaction with water; its fraction ionized depends on concentration. A dilute strong acid can have a higher pH than a concentrated weak acid. “Strong,” “concentrated” and “corrosive” are different descriptions.
Acid reacting with a hydroxide base commonly gives water and a salt. For 2 HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2 H₂O, two hydroxides require two donated protons. The salt formula follows Ca²⁺ and NO₃⁻ charges, then coefficients balance the reaction. In contrast, HCl + NH₃ → NH₄Cl transfers a proton without producing water in that molecular equation. “Salt plus water” is therefore a useful hydroxide pattern, not the definition of every acid-base reaction.
Neutralization describes the reaction, not a guaranteed final pH. Excess acid leaves an acidic mixture; excess base leaves a basic one. Even at stoichiometric equivalence, an acetate salt is basic and an ammonium salt acidic because their ions react with water. Strong acid–strong base equivalence is neutral in the ideal dilute model; neutral pH is 7.00 specifically at 25 °C.
H₂SO₄(aq) + 2 NaOH(aq) → Na₂SO₄(aq) + 2 H₂O(l)
Some acid reactions produce a gas rather than only water. Carbonates and bicarbonates react with acids to give carbon dioxide, water and a salt, and the fizzing is the visible clue. The mechanism is still proton transfer, the unstable carbonic acid formed simply falls apart.
For carbonate, two proton transfers give CO₃²⁻ + 2 H⁺ → CO₂(g) + H₂O(l). Bicarbonate needs only one: HCO₃⁻ + H⁺ → CO₂ + H₂O. Balance atoms and charge to distinguish these ratios. Gas escape helps drive the observed process forward; fizzing alone does not reveal how many moles reacted without a balanced equation.
CaCO₃(s) + 2 HCl(aq) → CaCl₂(aq) + H₂O(l) + CO₂(g)
An amphiprotic ion can donate a proton to a stronger base or accept one from a stronger acid. Its role is determined by the reaction partner, not its name alone.
Bicarbonate HCO₃⁻ sits between H₂CO₃ and CO₃²⁻ in a conjugate series, so it can react in either direction.
A proton donor, a species that gives away H⁺.
A proton acceptor, a species that takes on H⁺.
Two species differing by exactly one proton, such as NH₄⁺ and NH₃.
Common strong acids ionize essentially completely; H₂SO₄ has a strong first ionization and a separate weaker second ionization.
Water can donate or accept a proton, acting as an acid with bases and as a base with acids.
H⁺(aq) + OH⁻(aq) → H₂O(l)
Identify the conjugate acid-base pairs in NH₃ + H₂O → NH₄⁺ + OH⁻.
Try it first: Track the hydrogen atoms, one of them changes owner.
0 of 3 steps revealed.
Write the molecular and net ionic equations for complete neutralization of HNO₃(aq) with Ca(OH)₂(aq).
Try it first: Count hydroxides per dissolved base formula unit.
0 of 4 steps revealed.
What is the conjugate base of HCO₃⁻, and what is its conjugate acid?
0 of 3 steps revealed.
Show bicarbonate acting as a base with H₃O⁺ and as an acid with OH⁻.
Try it first: Write the conjugate products for gaining or losing one proton.
0 of 3 steps revealed.
| Mistake | Why it's wrong | Check instead |
|---|---|---|
| Treating strong and concentrated as the same word. | Strength describes the fraction that ionises, concentration describes how much solute is present. | Ask whether the substance is on the strong list, then read the molarity separately. |
| Saying the conjugate base of H₂SO₄ is SO₄²⁻. | A conjugate differs by only one proton, not two. | Remove a single H⁺ to get HSO₄⁻. |
| Assuming neutralisation always gives a neutral pH 7 solution. | The salt formed can itself be acidic or basic when a weak acid or weak base is involved. | Only a strong acid with a strong base gives a neutral salt solution. |
| Splitting a weak acid into ions in a net ionic equation. | Weak acids remain mostly as molecules in solution. | Write weak acids and weak bases as intact formulas. |
Scroll horizontally if needed to read all columns.
After the lesson · Question bank
Work through new problems on your own. The lesson's quick checks and worked examples stay above if you need to review a step.
25 topic questions across 3 difficulty levels.
Loading practice questions…
A Bronsted-Lowry acid donates a proton and a base accepts one, producing a conjugate base and conjugate acid that differ from their partners by exactly one H⁺. Strong acids and bases ionise completely, so their neutralisation reduces to H⁺ + OH⁻ → H₂O, while weak acids stay largely intact and appear whole in the net ionic equation. Recognising the small list of strong acids and bases is what makes these predictions fast.
Lesson: Not marked completed
Marking a lesson completed records that you finished reading it. Practice establishes mastery separately. Saved on this device.
Try a short set of different questions to check what you can do independently.
An optional video to support this lesson.
Loading video resources…
External resources belong to their respective creators. Chem Help is not affiliated with or endorsed by these providers. Links open the original provider; their terms apply.
Source attribution for this lesson has not been verified. Missing source records do not establish originality or reuse permission.